Getdp D1
Hi, In Getdp reference manual you say (p.26) that when you apply D1 to [ux, uy] and when the first basis-function-type in dFunction is set to BF_NodeX_D12 for component X and BF_NodeY_D12 for component Y, you obtain the vector [\partial u_x/\partial x,\partial u_y/\partial y,\partial u_x/\partial y+\partial u_y/\partial x]. My question is how do you make the two-dimensional vector [ux, uy]. Could you bring an example? Many Thanks, Philippe